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On a modified chess board 10x10, A and B are two persons moving towrds each other with the same speed. A can move right and up while B can move left and down.
The no of ways in which they can meet at the same point during their trip is ? ?

nick furie , 8 Years ago
Grade 12
anser 2 Answers
nick furie

Last Activity: 8 Years ago

is

M srinivas

Last Activity: 7 Years ago

Let us take a 10*10 chessboard.
In this, A is at one end and B is at the other end of the big square ( 10*10 ).
So, if we take B only takes two left steps and one down step and A takes the remaining 8 right steps and 9 up steps.
so total no.of steps needed so that they can meet up are 10 horizontal steps and ten vertical steps.
so, if we select 10 steps out of these 20 then that should give the number of ways they can meet up beacuse if we select these 10 steps automatically reamining steps will be selected.
So answer would be 20C10.
(Illustrate the figure to get an idea of what I said above)

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